This creates a composite section with point loadings (two) over four spans. Typical 3/4" (19 mm) 4'x8' sheets are installed (glued and screwed) perpendicular to the 2"x4" floor girder joist. RE: Subfloor load for Pool Table TBone2000 (Computer) Is there any sub-flooring to help carry the leg loads? You need to check this out better. How many floor boards would this require and would the tongue and groove joints be strong enough to transfer the load evenly across several floor board? Twenty-four inches is a fairly large joist spacing and a 575# point load is large for a piece of 3/4 inch think flooring. The table leg weight would need to be distributed across 24.5 inches of flooring. A leg contact area of 28 inches is about 5.3" x 5.3". The width of 3/4 inch floor required to provide 2.3 in^3 = b = 2.3 x 6 / (0.75 x 0.75) = 24.5 inches. Assuming an allowable bending stress of about Fb = 1500 psi (maybe even a little bit higher), the required section modulus of the flooring is s = M/Fb = 2.3 in^3. Therefore, the load per leg could be 575#. To that I would add at least the weight of one person, leaning or sitting on the table, above the leg. The table leg weight is 1300# / 4 = 325#. The bigger problem is the bending of the 3/4" thick flooring between the joists which are spaced at 24 inches. The psi of bearing (compression perpendicular to the wood grain) is not the main concern. Sorry, but I don't think boo1 has answered the question.
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